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If 3.0 moles of a gas are in a 60.0 liters container at 400.0 K, what is the pressure, in atm, inside
the container?
A.
0.61 atm
B.
16 atm
C.
1.6 atm

Respuesta :

Answer:

C. 1.6 atm

Explanation:

PV = nRT

Solve for P --> P = nRT/V

n = 3.0 mol

R = 0.08206 L atm / mol K

T = 400.0 K

V = 60.0 L

P = (3.0)(0.08206)(400.0) / (60.0) = 1.6 atm

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