A rectangular box is 6 inches wide 10 inches long and 2 inches tall how much wrapping paper is needed to cover the box exactly

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Answer:

184 in²

Step-by-step explanation:

Given :

Width, w = 6 inches

Length, l = 10 inches

Height, h = 2 inches

To obtain how much wrapping paper is needed ; we take the surface area of the box

Surface area = 2(lw + lh + wh)

Surface area = 2((6*10) + (6*2) + (10*2))

Surface area = 2(60 + 12 + 20)

Surface area = 2(92)

Surface area = 184 in²

The amount of wrapping paper needed = 184 in²