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What is the energy change per gram of ice when an iceberg composed of pure water, cp = 2.06 j/(gk, is heated from -25°c to -15°c?

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sebassandin

Answer:

[tex]Q=20.6\frac{J}{g}[/tex]

Explanation:

Hello there!

In this case, according to the equation for the calculation of the heat during a heating process:

[tex]Q=mC(T_f-T_i)[/tex]

It is possible to compute it per gram of ice by just removing m from the equation by dividing at both sides. Next we plug in the given specific heat and the final and initial temperatures to obtain:

[tex]Q=2.06\frac{J}{g\°C}[-15\°C-(-25\°C)] \\\\Q=20.6\frac{J}{g}[/tex]

Best regards!