Answer:
[tex]y_{max} = 1208.8 m[/tex]
Explanation:
As we know that flare is shot at an angle of 62.9 degree
and the initial speed is given as
[tex]v_i = 173 m/s[/tex]
now we have
[tex]v_y = v sin\theta[/tex]
[tex]v_y = 173 sin62.9[/tex]
[tex]v_y = 154 m/s[/tex]
now the maximum height of the flare is given as
[tex]y_{max} = \frac{v^2}{2g}[/tex]
[tex]y_{max} = \frac{154^2}{2(9.81)}[/tex]
[tex]y_{max} = 1208.8 m[/tex]
