When an airplane leaves the runway, its angle of climb is 18° and it's speed is 275ft per second. how long will it take the plane to climb to an altitude of 10000ft?

Respuesta :

 Draw a rt. triangle: 
The bottom is the ground, the hypotenuse is the flight path, the upright is the line from the ground to the planes position after one minute (60 seconds). 
p = altitude of plane, h = flight path 

h = (275)(60) = 16500 

Using the law of sine: 
sin (18) = p/16500 
p = [sin(18)](16500) 
p= 5098.8 ft