Nitromethane (CH3NO2) burns in air to produce significant amounts of heat. 4 CH3NO2 (l) + 3 O2 (g) → 4 CO2 (g) + 6 H2O (l) + 2 N2 (g) , ΔHorxn = -2836 kJ If 1,273 kJ of heat are produced from the burning of nitromethane, how many grams of nitromethane were burned?

Respuesta :

Answer:

27.38 g

Explanation:

  • CH₃NO₂ (l) + 3O₂ (g) → 4CO₂ (g) + 6H₂O (l) + 2N₂ (g)   ΔHorxn = -2836 kJ

The value of ΔHorxn tells us that when 1 mol of CH₃NO₂ is burned, 2836 kJ of heat are produced. With that in mind we can calculate how many moles of CH₃NO₂ were burned when 1273 kJ of heat were produced:

  • 1273 kJ * 1mol / 2836 kJ = 0.4489 mol

Then we convert 0.4489 moles of CH₃NO₂ to grams, using its molar mass:

  • 0.4489 mol * 61 g/mol = 27.38 g

27.38 g

What is Nitromethane?

Nitromethane is used as a fuel in motors racing, particularly drags racing, as well as for radio-control model power boats, cars, planes, and helicopters. In this context, nitromethane is commonly referred to as "nitro fuel"

How much does nitromethane fuel cost per gallon?

Nitromethane used to power the engines of NHRA Top Fuel dragsters and Funnky Cars costs about $16 US per gallon.

CH₃NO₂ (l) + 3O₂ (g) → 4CO₂ (g) + 6H₂O (l) + 2N₂ (g)   ΔHorxn = -2836 kJ

The value of ΔHorxn tells us that when 1 mol of CH₃NO₂ is burned, 2836 kJ of heat is produced. With that in mind we can calculate how many moles of CH₃NO₂ were burned when 1273 kJ of heat were produced:

1273 kJ * 1mol / 2836 kJ = 0.4489 mol

Then we convert 0.4489 moles of CH₃NO₂ to grams, using its molar mass:

0.4489 mol * 61 g/mol = 27.38 g

Learn more about Nitromethane here https://brainly.com/question/10833010

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