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An engineer on the ground is looking at the top of a building. The angle of elevation to the top of a building is 38Á. The engineer knows the building is 300 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?

Respuesta :

E - engineer
B - base of the building
T - top of the building
x - distance from the engineer to the base of the building 

[tex]\tan{\angle{E}}= \frac{BT}{BE} \\ \\ \tan{38^o}= \frac{300}{x} \\ \\x= \frac{300}{\tan{38^o}} \\ \\x \approx 384[/tex] 
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