The population of a type of local bass can be found using an infinite geometric series where a1 = 72 and the common ratio is one fourth. Find the sum of this infinite series that will be the upper limit of this population.

Respuesta :

Sum of infinite sequence is given by S∞ = a/(1 - r); where a is the first term and r is the common ratio.
S∞ = 72/(1 - 1/4) = 72/(3/4) = 96.

Answer:

96

Step-by-step explanation:

Given that the population of a type of local bass can be found using an infinite geometric series.

I term  a1 = 72

Common ratio r = [tex]\frac{1}{4}[/tex]

We know that sum of n terms of geometric series where |r|<1 is

[tex]S_{n} =\frac{a(1-r^n}{1-r}[/tex]

Sum of infinite terms would be limit of this Sn as n tends to infinity.

When r <1 we have r^n will tend to 0 as n tends to infinity.

Hence Sum of infinite terms

=[tex]\frac{a}{1-r} =\frac{72}{1-\frac{1}{4} } \\=96[/tex]

Sum of infinite series = 96