Respuesta :

Azieq
left hand side
sin^3z × ( 1 - sin^2z ) = RHS
let sin z = y
y^3 × ( 1 - y^2 ) = RHS
y^3 - y^6 = RHS
sin^3z - sin^6z = RHS

the answer at RHS should be to the power of 6 . u better check it next time