Answer:
[tex]W \le 6[/tex]
Step-by-step explanation:
Given
[tex]Area = 60ft^2\ (max)[/tex]
[tex]Length = 10ft[/tex]
Required
Represent the width as an inequality
First, we represent the area as an inequality.
[tex]Area = 60ft^2\ (max)[/tex]
max as used above means less than or equal to.
So, we have:
[tex]Area \le 60[/tex]
The area of a rectangle is:
[tex]Area = L * W[/tex]
So, we have:
[tex]L * W \le 60[/tex]
Substitute 10 for L
[tex]10 * W \le 60[/tex]
Divide both sides by 10
[tex]\frac{10 * W}{10} \le \frac{60}{10}[/tex]
[tex]W \le \frac{60}{10}[/tex]
[tex]W \le 6[/tex]
