Answer:
2x [tex]\sqrt[3]{2x}[/tex] - [tex]\sqrt[3]{2x}[/tex]
Step-by-step explanation:
you can take the cubed root of [tex]\sqrt{16x^4}[/tex] and make it become the cubed root of ∛(2)³ · 2 · x³ · x which would equal 2x· ∛2x
I don't believe 2x· ∛2x - ∛2x can be simplified
