Answer:
Mass = 99.2 g
Explanation:
Given data:
Volume of oxygen = 15 L
Mass of oxygen = ?
Pressure of oxygen = 75 psi ( 75/14.696 = 5.10 atm)
Temperature of oxygen = 28°C (28+273 = 301 K)
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
n = PV/RT
n = 5.10 atm× 15 L / 0.0821 atm.L/ mol.K × 301 K
n = 76.5 atm.L/24.71 atm.L/ mol
n = 3.1 mol
mass of oxygen:
Mass = number of moles × molar mass
Mass = 3.1 mol × 32 g/mol
Mass = 99.2 g
