It will cost Sam "1.45 p. per hr" to use an 85W laptop and a 60W lamp. To understand the calculation, check below.
According to the question,
Electricity cost = 10 p per unit
Laptop power = 85 W
Lamp power = 60 W
We know the standard unit, KW/hr = 1000 W/hr
then,
= 85 + 60
= 145 W
By fractioning,
= [tex]\frac{145}{1000}[/tex]
= 0.145 KWH
hence,
The cost will be:
= 0.145 × 10 p
= 1.45 p. per hr
Thus the above approach is correct.
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