Answer:
The equation of the line in slope-intercept form is y = -x + 1
Step-by-step explanation:
The slope-intercept form of the linear equation is y = m x + b, where
The rule of the slope is m = [tex]\frac{y2-y1}{x2-x1}[/tex] , where
∵ f(x) = y ⇒ is the function of the set of ordered pairs (x, y)
∴ f(3) = -2 is the point (3, -2)
∴ f(0) = 1 is the point (0, 1)
∴ x1 = 3 and y1 = -2
∴ x2 = 0 and y2 = 1
→ Substitute them in the rule of the slope to find it
∵ m = [tex]\frac{1--2}{0-3}[/tex] = [tex]\frac{1+2}{-3}[/tex] = [tex]\frac{3}{-3}[/tex]
∴ m = -1
→ Substitute it in the form of the equation above
∵ y = -1(x) + b
∴ y = -x + b
∵ b is the value of y at x = 0
∵ at x = 0, y = 1
∴ b = 1
∴ y = -x + 1
∴ The equation of the line in slope-intercept form is y = -x + 1
