Answer:
The change in entropy = -0.6306 kJ/k
Explanation:
The mass of air = 2kg
In a Compressed isothermal process T₁ = T₂ = 27⁰ C
The initial pressure = 100 kPa
Final volume V₂ = 1/3 (V₁)
i.e. V₂/V₁ = 1/3
Rate ( gas constant) R = 0.287 kJ/kgk
The change in an entropy process is:
ΔS = m × R × In(V₂/V₁)
ΔS = 2 × 0,287 × In (1/3)
ΔS = -0.6306 kJ/k
