Answer:
[tex]\huge\boxed{\sf p = 932.2 \ millibars}[/tex]
Step-by-step explanation:
[tex]\sf v(p) = 5.7\sqrt{998 - p} \\\\Given \ that \ v(p) = 49.3 m/s. Also \ Finding \ p\\\\49.3 = 5.7 \sqrt{998-p} \\\\Divide \ both \ sides \ by \ 5.7\\\\49.3 / 5.7 = \sqrt{998-p} \\\\8.649 = \sqrt{998-p} \\\\Square \ both \ sides\\\\74.8 = 998 - p\\\\p = 998 - 74.8\\\\p = 923.2\ millibars\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
