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If a seagull drops a shell from rest at a height of 16 m , how fast is the shell moving when it hits the rock

Respuesta :

mkostyuchenko2339

Answer:

We know:

V1 = 0m/s

a = 9.8m/s

D = 16m

So we can solve for V2 with a kinematic equation.

V2^2 = 2a*D

V2^2 = 2(9.8)(16)

V2^2 = 313.6

V2 = 17.7m/s

Explanation:

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