Suppose that you 2 two dice and observe the numbers showing on the uppermost surfaces of the dice. What is the probability that the sum is less than 5

Suppose two dice are observed; Then the number of outcomes in first dice = 6 i.e (1,2,3,4,5,6) and also the number of outcomes in second dice = 6 as well i.e (1,2,3,4,5,6)

The total number of outcomes of two dices = 6×6 = 36

Now for a sum that is less than 5; their outcomes are [(1,1) ,(1,2) , (1,3) ], [(2,1), (2,2) ], (3,1) = 6 outomes

The total number of outcomes for the sum that is less than 5 = 6

∴

The required probability (P) = Total number of outcomes for the sum that is less than 5 / Total number of outcomes of two dices

The required probability (P) = 6/36

The required probability (P) = 1/6

andromache andromache · Answer 2 · 2022-03-29T14:24:20+02:00

The probability that the sum is less than 5 is [tex]1\div 6[/tex].

Calculation of the probability:

Since two dice are observed.

So the number of outcomes in first dice = 6 i.e (1,2,3,4,5,6) and also the number of outcomes in second dice = 6 as well i.e (1,2,3,4,5,6)

Now

The total number of outcomes of two dices = 6(6) = 36

Now for a sum that is less than 5; their results should be [(1,1) ,(1,2) , (1,3) ], [(2,1), (2,2) ], (3,1) = 6 outomes

So here the probability is

[tex]= 6/36\\\\= 1/6[/tex]

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