Answer:
0.9594
Step-by-step explanation:
Given that:
Sample size (n) = 64
p = 30% = 0.3 ; 1 - p = 0.7
Probability that sample proportion is greater than 0.2
Mean (m) = n*p = 64 * 0.3 = 19.2
Standard deviation (s) = √n*p*(1-p) = √(19.2*0.7)= 3.67
0.2 of 64 = 12.8
Z > [(x - m) / s]
Z > (12.8 - 19.2) / 3.67
Z > (-6.4 /3.67)
Z > - 1.7438
= 0.9594
