Answer:
both negative
Step-by-step explanation:
Descartes rule of signs tells us how many positive and negative real roots a polynomial has.
Given
f(x) = x² + 5x + 6 , with signs
+, +, + ← no change of signs, thus no positive zeros
f(- x) = (- x)² + 5(- x) + 6 = x² - 5x + 6 , with signs
+, -, + ← with 2 changes of signs. thus 2 negative zeros
Answer:
B) Both Negative
Step-by-step explanation:
[tex](x^2+5x+6)\\=(x^2+2x+3x+6)\\=x(x+2) + 3(x+2)\\=(x+3)(x+2)\\Hence,\ as\ their\ factors\ are\ (x+3)\ and\ (x+2)\ their\ zeroes\ are\ (-3)\ and\ (-2)\ respectively..\\As\ they\ both\ are\ negative..\ the\ answer\ is\ b)\\\[/tex]
