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A force of 6.00 N acts in the positive direction on a 3.00 kg object, originally traveling at +15.0 m/s, for 10.0 s. (a) What is the object’s change in momentum?

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Answer:

60 kg m/s

Explanation:

F= Force = 6 N

m = Mass of object = 3 kg

u = Initial velocity = 15 m/s

t = Time = 10 s

v = Final velocity

[tex]\Delta p[/tex] = Change in momentum

Force is given by

[tex]F=\dfrac{\Delta p}{t}\\\Rightarrow Ft=\Delta p\\\Rightarrow \Delta p=6\times 10\\\Rightarrow \Delta p=60\ \text{Ns}[/tex]

The change in  momentum of the object is 60 kg m/s.

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