Answer:
Step-by-step explanation:
[tex]\frac{1}{2}(x+15) = 2 + \frac{3}{4}(x-4)[/tex]
To make this easier, to get ride of the fractions, we can multiply both sides by 4
[tex]2(x+15) = 8 + 3(x-4)[/tex]
now use the distributive property
[tex]2x + 30 = 8 + 3x - 12\\[/tex]
now we want to isolate x to one side and isolate all the constants to the other
[tex]2x - 3x = 8 - 12 - 30\\[/tex]
now simplify
[tex]-x = -34\\x = 34[/tex]
to test, we can plug in back to the original
[tex]\frac{1}{2}(34+15) = \frac{49}{2}\\\frac{8}{4} + \frac{3}{4}(34-4) = \frac{8}{4} + \frac{90}{4} = \frac{98}{4} = \frac{49}{2}[/tex]
it works
