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The average height of an apple tree is 4.00 m how long will it take for an apple falling from that height to reach the ground given G equals -9.8 m a second squared

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onyebuchinnaji

Answer:

The time taken for the apple to reach the ground is 0.9 s

Explanation:

Given;

height of the apple tree, h = 4 m

acceleration due to gravity, g = 9.8 m/s²

The time taken for the apple to reach the ground is given by;

[tex]h = \frac{1}{2}gt^2\\\\t^2 = \frac{2h}{g}\\\\t = \sqrt{\frac{2h}{g}}\\\\t = \sqrt{\frac{2*4}{9.8}}\\\\t = 0.9 \ s[/tex]

Therefore, the time taken for the apple to reach the ground is 0.9 s

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