Evaluate h(x) = -2x +9
when x= -2,0, and 5.
h( - 2) =
h(0) =
h(5)=

Answer:
[tex] f(-2) = 13 [/tex]
[tex] f(0) = 9 [/tex]
[tex] f(5) = -1 [/tex]
Step-by-step explanation:
Given:
[tex] f(x) = -2x + 9 [/tex]
Required:
Find,
h(-2); h(0), and h(5)
SOLUTION:
Plug in the value of x into [tex] f(x) = -2x + 9 [/tex] in each case as follows:
[tex] f(-2) = -2(-2) + 9 [/tex]
[tex] f(-2) = 4 + 9 [/tex]
[tex] f(-2) = 13 [/tex]
[tex] f(0) = -2(0) + 9 [/tex]
[tex] f(0) = 0 + 9 [/tex]
[tex] f(0) = 9 [/tex]
[tex] f(5) = -2(5) + 9 [/tex]
[tex] f(5) = -10 + 9 [/tex]
[tex] f(5) = -1 [/tex]
The value of h(x) when x= -2,0, and 5 is; 13, 9 and -1 respectively.
The function, h(x) given is; h(x) = -2x +9 .
As such, evaluation of h(x) when x = 2,0, and 5 is as follows;
For x = -2
For x = 0
For x = 5
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