Respuesta :

Answer:

[tex] f(-2) = 13 [/tex]

[tex] f(0) = 9 [/tex]

[tex] f(5) = -1 [/tex]

Step-by-step explanation:

Given:

[tex] f(x) = -2x + 9 [/tex]

Required:

Find,

h(-2); h(0), and h(5)

SOLUTION:

Plug in the value of x into [tex] f(x) = -2x + 9 [/tex] in each case as follows:

[tex] f(-2) = -2(-2) + 9 [/tex]

[tex] f(-2) = 4 + 9 [/tex]

[tex] f(-2) = 13 [/tex]

[tex] f(0) = -2(0) + 9 [/tex]

[tex] f(0) = 0 + 9 [/tex]

[tex] f(0) = 9 [/tex]

[tex] f(5) = -2(5) + 9 [/tex]

[tex] f(5) = -10 + 9 [/tex]

[tex] f(5) = -1 [/tex]

The value of h(x) when x= -2,0, and 5 is; 13, 9 and -1 respectively.

The function, h(x) given is; h(x) = -2x +9 .

As such, evaluation of h(x) when x = 2,0, and 5 is as follows;

For x = -2

  • h(-2) = -2(-2) +9

  • h(-2) = 4 +9

  • h(-2) = 13

For x = 0

  • h(0) = -2(0) +9

  • h(0) = 0 + 9

  • h(0) = 9

For x = 5

  • h(5) = -2(5) +9

  • h(5) = -10 +9

  • h(5) = -1

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