contestada

A rectangle has an area of 352 square feet. Its widih is ten feet less than twice the length Find the measures of the length and width of the rectangle.​

Respuesta :

Answer:

The Length is 16.

The width is 22.

Step-by-step explanation:

[tex]Area=Width*Length\\352=(2L-10)*(L)\\352=2L^2-10L\\0=2L^2-10L-352\\x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\b=-10; a=2; c=-352\\ x=\frac{10+/-\sqrt{100-4(-352)*(2)} }{2*2} \\x=\frac{10+/-\sqrt{100+2816)} }{4}\\x=\frac{10+/-\sqrt{2916)} }{4}\\x=\frac{10+/-54 }{4}\\x=64/4=16[/tex]