Let's see what to do buddy....
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Step (1)
Express taxi charges 2.50 $ per mile.
So if each mile equals x the taxi charges 2.50 x.
There's the starting fare too.
So ;
Express taxi charges by the following function :
[tex]f(x) = 2.5x + 10[/tex]
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Step (2)
Speedy taxi charges 3 $ per mile.
So if each mile equals x the taxi charges 3x .
There's no starting fare.
So ;
Speedy taxi charges by the following function :
[tex]g(x) = 3x[/tex]
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Step (3)
To find that after how many miles is the cost of both taxi services the same , we must equal their functions.
Then solve for x .
So we have :
[tex]f(x) = g(x)[/tex]
[tex]2.5x + 10 = 3x[/tex]
Subtract the sides of the equation minus 2.5x :
[tex]10 = 0.5x[/tex]
[tex]10 = \frac{1}{2}x \\ [/tex]
Multiply the sides of the equation by 2 :
[tex]x = 20[/tex]
So after 20 miles both taxi services have the same cost.
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And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
