An airline makes 200 reservations for a flight who holds 185 passengers. The probability that a passenger arrives for the flight is 0.9 and the passengers are assumed to be independent. Use the normal approximation of Binomial distribution to answer the following questions.
(a) Approximate the probability that all the passengers who arrives can be seated.
(b) Approximate the probability that there are empty seats.
(c) Approximate the number of reservations that the airline should make so that the probability that everyone who arrives can be seated is 0.95 [Hints: since the number of reservations must be integers, please approximate your answer to an integer.]

Respuesta :

Answer:

A=0.9

B=0.855

C=198

Step-by-step explanation:

Let X be the binomial random variation with parameters given bellow as

n=200

p=1-0.9=0.1

Note that the value of Z is approximate standard random normal variable with the values of Ф gotten from table

Kindly find attached a detailed solution of the problem with the right annotation and symbols

Ver imagen samuelonum1
Ver imagen samuelonum1