Kim drove from Mathtown at (-2, 5) to Geometryville at (3, -1) to Algebra Springs at (-6, -5), and then back to Mathtown. Find the total distance Kim traveled to the nearest hundredth.

Kim drove from Mathtown at 2 5 to Geometryville at 3 1 to Algebra Springs at 6 5 and then back to Mathtown Find the total distance Kim traveled to the nearest h class=

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Answer:

Option (3)

Step-by-step explanation:

To solve this question we will use the formula,

Distance (d) between two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex],

d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Distance between Mathtown (-2, 5) to Geometryville (3, -1)

[tex]d_1=\sqrt{(3+2)^2+(-1-5)^2}[/tex]

    [tex]=\sqrt{25+36}[/tex]

    [tex]=\sqrt{61}[/tex]

    [tex]=7.81[/tex]

Distance between Geometryville (3, -1) and Algebra Springs (-6, -5)

[tex]d_2=\sqrt{(3+6)^2+(-1+5)^2}[/tex]

    [tex]=\sqrt{81+16}[/tex]

    [tex]=\sqrt{97}[/tex]

    [tex]=9.85[/tex]

Distance between Algebra Springs (-6, -5) and Mathtown (-2, 5)

[tex]d_3=\sqrt{(6-2)^2+(5+5)^2}[/tex]

    [tex]=\sqrt{16+100}[/tex]

    [tex]=\sqrt{116}[/tex]

    [tex]=10.77[/tex]

Now total distance traveled by Kim = [tex]d_1+d_2+d_3[/tex]

                                                           = 7.81 + 9.85 + 10.77

                                                           = 28.43

Therefore, Option (3) will be the answer.

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