(a) The angle of refraction for the ray inside the glass will be 19.26°.
(b) It is proved that the rays in the air on either side of the glass are parallel to each other
When a ray of light passes through a different medium some part of the light gets reflected and some part gets refracted by changing its angle in the different medium this angle is called the angle of refraction and the phenomenon is called refraction of light.
It is given that,
The angle of incidence = 30.0°
Index of reflection of glass = 1.52
(a) For finding the angle of the refraction for the ray inside the glass we will use Snell's Law
[tex]\dfrac{Sini}{Sinr} =\mu[/tex]
Put the value into the formula
[tex]Sinr=\dfrac{Sini}{\mu} =\dfrac{Sin30}{1.52}[/tex]
[tex]r=Sin^{-1}(0.329)[/tex]
[tex]r=19.26^o[/tex]
(b) Now for proof of [tex]Sin\ i =Sin\ e[/tex]
The incident ray and emerging ray are equal then the ray will be parallel.
We need to prove that the rays in the air on either side of the glass are parallel to each other.
Using the formula for emerging ray
[tex]\dfrac{Sin\ e}{Sin\ r} = \mu[/tex]
[tex]Sin\ e=\mu Sin \ r=1.52\times Sin19.26[/tex]
By putting the values in the formula
[tex]e=Sin^{-1}(1.52\times0.3289)[/tex]
[tex]e=30^o[/tex]
Since the incident angle and the emerging angle are equal
[tex]Sin \ i=Sin \ e[/tex]
Thus incident and emerging rays) are parallel to each other.
(a) So the angle of refraction for the ray inside the glass will be 19.26°.
(b) It is proved that the rays in the air on either side of the glass are parallel to each other
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