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07-10-2020
Mathematics
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What are the roots of f(x)=(x-6)^2(x+2)^2
Respuesta :
11qq11
11qq11
07-10-2020
f(x)=0
⇒(x−6)^2. (x+2) ^2 =0
⇒(x−6)^2=0, (x+2)^2=0
⇒x=6,6 ⇒x=−2,−2.
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