Answer:
Something doesn't make sense. The time when his height is 0 is time t=0 and t=25.
The vertex would be halfway in between at time t=(0+25)/2 = 12.5 seconds.
But plugging that in, we get a height of:
3.90625 inches
I think you must have a typo... let's try this equation instead:
h(t) = (-0.25t)(t - 25)
In that case, the maximum at h(12.5) is 39.0625 inches.
Answer:
No, the function for his height has him just barely clearing 39 inches. He can't clear 42 inches.
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