Given :
Mass of foil , m = 1.68 g .
Density of foil , [tex]\rho=7.31\ g/cm^3[/tex] .
To Find :
The thickness of the foil .
Solution :
Let , length and breadth is l and b respectively .
Also , height be h .
Volume is given by :
[tex]V=l\times b\times h[/tex]
Density is given by :
[tex]\rho=\dfrac{m}{V}\\\\V=\dfrac{m}{\rho}\\\\l\times b\times h=\dfrac{1.68}{7.31}\\\\l\times b\times h=0.23\\\\h=\dfrac{0.23}{lb}[/tex]
Therefore , thickness of the foil is [tex]\dfrac{0.23}{lb}[/tex] .
Hence , this is the required solution .
