Given :
A force of 150 N is exerted 22◦ north of east.
To Find :
The northward component of force .
Solution :
The angle between the force and east direction is 22° .
So , component of Force F in north direction is given by :
[tex]Fsin\ \theta\\\\150\times sin\ 22^o\\\\56.19\ N[/tex]
Therefore , the component of force in northward direction is 56.19 N .
Hence , this is the required solution .
