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the radioisotope actinium-225 has a half-life of 10 days. I begin with 16 kg of this isotope, how much will remain after 40 days?

Respuesta :

Yipes
[tex]\tau_{\frac{1}{2}}=10days\\ t=40days\\ N_{0}=16kg\\\\\\ N(t)=16kg*(\frac{1}{2})^{\frac{40}{10}}=16kg*(\frac{1}{2})^{4}=16kg*\frac{1}{16}=1kg[/tex]

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