Respuesta :

[tex]5x=3x^2+1\\3x^2-5x+1=0\\x= \frac{-(-5) \pm \sqrt{(-5)^2-(4 \times 3 \times 1)}}{2 \times 3}\\=\frac{5\pm\sqrt{25-12}}{6}\\=\frac{5\pm\sqrt{13}}{6}\\=\frac{5+\sqrt{13}}{6}\,or\,\frac{5-\sqrt{13}}{6}[/tex]

Answer:

It is D

Don't mind this :P