Answer:
[tex]\huge\boxed{Second\ Number = 42}[/tex]
Step-by-step explanation:
Let the consecutive even numbers be x,x+2,x+4, x+ 6, x+ 8 and x+10
So, the given condition is:
x+x+2+x+4+x+6+x+8+x+10 = 270
6x + 30 = 270
Subtracting both sides by 30
6x = 270 - 30
6x = 240
Dividing both sides by 6
x = 40
So,
First Number = x = 40
Second Number = x+2 = 40+2 = 42
Third Number = x+4 = 40+4 = 44
Fourth Number = x+6 = 40+6 = 46
Fifth Number = x+8 = 40+8 = 48
Sixth Number = x+10 = 40+10 = 50
