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The first two steps in determining the solution set of the system of equations, y = x2 - 6x + 12 and y = 2x - 4
algebraically are shown in the table.
Step
Step 1
Step 2
Equation
x2 - 6x + 12 = 2x4
x2–8x+16=0
Which represents the solution(s) of this system of equations?
O (4,4)
O 64,-12)
0 (4, 4) and (44, 12)
O (-4, 4) and (4, 12)
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Answer:

(4, 4 )

Step-by-step explanation:

Given the 2 equations

y = x² - 6x + 12 → (1)

y = 2x - 4 → (2)

Substitute y = x² - 6x + 12 into (2)

x² - 6x + 12 = 2x - 4 ( subtract 2x - 4 from both sides )

x² - 8x + 16 = 0 ← in standard form

(x - 4)² = 0 ← in factored form

x - 4 = 0 ⇒ x = 4

Substitute x = 4 into (2) for corresponding value of y

y = 2(4) - 4 = 8 - 4 = 4

Solution is (4, 4 )

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