Answer:
28,750 turns
Explanation:
According to the given situation the solution of number of turns in the solenoid is shown below:-
Number of turns in the solenoid is
[tex]B = \frac{\mu_0NI}{I}[/tex]
[tex]N = \frac{BI}{\mu_oI}[/tex]
[tex]N = \frac{(9.20)(0.550)}{4\pi\times10{-7}(140)}[/tex]
[tex]N = \frac{5.06}{0.000176}[/tex]
= 28,750 turns
Therefore for computing the number of turns in the solenoid we simply applied the above formula.
So, the right answer of number of turns in the solenoid is 28,750 turns.
