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A motorcycle has a constant acceleration of 3.49 m/s2. Both the velocity and acceleration of the motorcycle point in the same direction. How much time is required for the motorcycle to change its speed from (a)29.0 to 39.0 m/s, and (b)59.0 to 69.0 m/s?

Respuesta :

lublana

Answer:

(a)2.865 s

(b)2.865 s

Explanation:

We are given that

Acceleration,a=[tex]3.49 m/s^2[/tex]

a.Initial speed,u=29 m/s

Final speed,v=39 m/s

We know that

[tex]t=\frac{v-u}{a}[/tex]

Using the formula

[tex]t=\frac{39-29}{3.49}=2.865 s[/tex]

b.Initial speed,u=59 m/s

Final speed,v=69 m/s

Again using the formula

[tex]t=\frac{69-59}{3.49}=2.865 s[/tex]

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