Answer:
84feet
Step-by-step explanation:
Given the height of the ball modelled by the equation h(t)=16t²+84 after t secs. At the maximum height, the velocity of the ball is zero.
Velocity V is the change of rate of displacement.
V = dh/dt = 32t
0 = 32t
t = 0secs
at t = 0;
h(0) = 16(0)²+84
h(0) = 84feet
This shows that the maximum height of the ball is 84feet
