contestada

A helium gas tank at 3.00 x 103 mm Hg is cooled from 500 Kelvin to 300 Kelvin. What is the final pressure of the helium gas in the steel tank?

Respuesta :

sebassandin

Answer:

[tex]P_2=1.80x10^3mmHg[/tex]

Explanation:

Hello,

In this case, we use the Gay-Lussac's law to understand the pressure-temperature relationship a directly proportional relationship:

[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]

Thus, solving for the final pressure P2, we obtain:

[tex]P_2=\frac{P_1T_2}{T_1}=\frac{3.00x10^3mmHg*300K}{500K}\\ \\P_2=1.80x10^3mmHg[/tex]

Best regards.

Otras preguntas