Answer : The volume of 1 M NaOH solution required are, 400 mL
Explanation :
To calculate the volume of base, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=2\\M_1=2M\\V_1=100mL\\n_2=1\\M_2=1M\\V_2=?[/tex]
Putting values in above equation, we get:
[tex]2\times 2M\times 100mL=1\times 1M\times V_2[/tex]
[tex]V_2=400mL[/tex]
Therefore, the volume of 1 M NaOH solution required are, 400 mL
