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The x- and y- coordinates of moving particle are given by the parametric equation x=4t^2 + t and y = 2-4t.


Find the magnitude of the velocity at t=2 seconds. The distance is measured in meters.


Round your answer to 1 decimal place.

Respuesta :

sqdancefan

Answer:

  17.5 m/s

Step-by-step explanation:

The magnitude of velocity is the root of the sum of the squares of the x- andy-velocities.

  x' = 8t +1

  y' = -4

At t = 2, the respective velocities are ...

  x'(2) = 8·2 +1 = 17

  y'(2) = -4

Then the velocity is ...

  v(2) = √(17^2 +(-4)^2) = √305

  v(2) ≈ 17.5 . . . . meters/second

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