Answer:
The correct answer to the following question will be "v = 3.30×10⁵ m/s".
Explanation:
Electron collisions may initially have led to a change or transition from, n = 1 to n = 3.
So,
Incident electrons lost (-6.5-(-2)) = -4.5 ev at energy.
From energy management,
⇒ [tex]\frac{1}{2}mv-\frac{1}{2}m(1.3\times 10^6)^2=-4.5ev(\frac{1.6\times 10^{-19}J }{ev})[/tex]
On taking "m" common, we get
⇒ [tex]m(v^2-(1.3\times 10^6)^2)=-1.44\times 10^{-18}[/tex]
⇒ [tex]9.11\times 10^{-31}(v^2-(1.3\times 10^6)^2)=-1.44\times 10^{-18}[/tex]
⇒ [tex]v^2-(1.3\times 10^6)^2=-1.58\times 10^{12}[/tex]
⇒ [tex]v=3.30\times 10^5 \ m/s[/tex]
