Respuesta :

Answer:

[OH] = b

[tex]5.01 \times {10}^{ - 10} mol {dm}^{ - 3} [/tex]

Explanation:

pOH = -log [OH]

9.3 = -log [OH]

[OH] = 10^-9.3

[OH] = 5.01 × 10^-10 M