The half life of carbon-14 is 5,730 years. ABOUT how old is a sample that has one-fourth of its carbon-14 unchanged?
a.10,000 years

b.15,100 years

c.11,400 years

d.5,700 years

Respuesta :

Answer:

C. 11400 years.

Explanation:

The time constant of the isotope is:

[tex]\tau = \frac{5730\,yr}{\ln 2}[/tex]

[tex]\tau = 8266.643\,yr[/tex]

The decay of the isotope is described by the following model:

[tex]\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }[/tex]

[tex]-\frac{t}{\tau} = \ln \frac{m(t)}{m_{o}}[/tex]

[tex]t = -\tau \cdot \ln \frac{m(t)}{m_{o}}[/tex]

[tex]t = -(8266.643\,yr)\cdot \ln \left(\frac{1}{4} \right)[/tex]

[tex]t \approx 11460.001\,yr[/tex]

The right answer is C.