Answer:
ΔH = 41.7 kj
Given data:
Mass of ethanol = 50 g
Heat required to vaporize = ?
Boiling point of ethanol = 78.3°C
Molar heat of vaporization = 38.6 kj/mol
Solution:
First of all we will calculate the number of moles.
Number of moles = mass / molar mass
Number of moles = 50 g/ 46.07 g/mol
Number of moles = 1.08 mol
ΔH = 38.6 kj/mol ×1.08 mol
ΔH = 41.7 kj
Explanation:
