benhimmel88
contestada

A circle has the equation (x−13)2+(y−1)2=4.
A: What is the center of the circle?
B: What is the radius of the circle?

Select two answers: one for question A, and one for question B.

A: (13,1)

B: 4

A: (−13,−1)

A: (−13,1)

A: (13,−1)

B: 2

B: 2–√

Respuesta :

nktselepov

An equation of circle has form

[tex](x-x_0)^2+(y-y_0)^2=r^2 \\ where\: x_0\: and\: y_0\: are\: the\: center[/tex]

So, the center is (13;1)

Now we need to find a radius

Let's create an equation

[tex] {r}^{2} = 4 \\ r = \sqrt{4} \\ r = 2[/tex]

So radius is 2

Otras preguntas