Answer:
$2018.016
Explanation:
Applying,
P = I²R.............. Equation 1
Where P = power, drawn by the oven, I = current drawn by the oven, R = resistance of the oven.
Given: I = 10 A, R = 2002 Ω
Substitute this values into equation 1
P = 10²(2002)
P = 100(2002)
P = 200200 W.
P = 200.2 kW
If the electric oven works 3 hours daily,
Then the total time it works in a week = 3×7 = 21 hours.
E(kWh) = P(kW)×t(h)
E = 200.2×21
E = 4204.2 kWh.
If 1 kWh of energy cost $0.48,
Then, 4204.2 kWh = $4204.2(0.48) = $2018.016
