Answer:
Oxidation number of Fe(iron) on right side of reaction arrow = (+2)
Explanation:
NADH+H+ + FMN FMNH2 + NAD+
FMNH2 - Reduced FMN (1,5-Dihydroriboflavin 5'-(dihydrogen phosphate)
The reactant that is reduced is Flavin mononucleotide(FMN)
QH2 + 2cyt c(fe³+) -----------------------> Q + 2Cytc ( fe²+) + 2H+
Oxidation number of Fe(iron) on right side of reaction arrow = (+2)
The equation of the transfer of two electrons from NADH to FMN is given below:
NADH + H⁺ + FMN ⟶ NAD⁺ + FMNH₂
The oxidation number of iron on the right side of the reaction arrow is +2 (Fe²⁺)
In the electron transport chain, electrons are passed from electron carriers such as NADH through various carriers and eventually to oxygen. Water and energy in the form of ATP is produced.
The electron carriers are organized into complexes; Complex I, II, III, and IV
In complex I, also known as NADH Dehydrogenase, electrons are passed from NADH to ubiquinone through an FMN-containing flavoprotein and several iron-sulfur centers.
The equation below shows how two electrons are passed from NADH to FMN:
NADH + H⁺ + FMN ⟶ NAD⁺ + FMNH₂
In complex III, electrons are transferred from coenzyme Q to cytochrome c, a single electron-carrier which contains iron. The equation for the electron transfer is given below:
QH₂ + 2 cyt c ( Fe³⁺) ⟶ Q + 2 cyt c ( Fe²⁺ ) + 2H⁺
In the reaction above, the two electron-carrier ubiquinone transfers its two electrons to two molecules of the one electron-carrier cytochrome c containing iron in the oxidized iron (iii) state, Fe³⁺. The electrons accepted reduces the Fe³⁺ in cytochrome c to Fe²⁺.
Therefore, the oxidation number of iron on the right side of the reaction arrow (reduced cytochrome c) is +2.
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